Consider the dissociation of acetic acid in water at equilibrium: CH3COOH = CH3COO-+ H+ You start with0.05 moles of acetic acid in 500 mL of water. At equilibrium, the pH of the solution is 2.873. What is theequilibrium constant of this reaction? Hint: You will need to calculate an antilog using a scientific c… Show more… Show more Science Chemistry CHEM 2123 Share QuestionEmailCopy link Comments (0)